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165 lines
4.4 KiB
JavaScript
165 lines
4.4 KiB
JavaScript
'use strict';
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/**
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* Takes an object and deletes all keys that are
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*
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* tagged as false by the passed in filter function
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*
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* @param {object} obj regular javascript object
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* @return {object} regular javascript object without null values or empty strings
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*/
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export function sanitize(obj, filterFn) {
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if(!filterFn) {
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// By matching null with a double equal, we can match undefined and null
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// http://stackoverflow.com/a/15992131
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filterFn = (val) => val == null || val === '';
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}
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Object
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.keys(obj)
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.map((key) => {
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if(filterFn(obj[key])) {
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delete obj[key];
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}
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});
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return obj;
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}
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/**
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* Sums up a list of numbers. Like a Epsilon-math-kinda-sum...
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*/
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export function sumNumList(l) {
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let sum = 0;
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l.forEach((num) => sum += parseFloat(num) || 0);
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return sum;
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}
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/*
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Taken from http://stackoverflow.com/a/4795914/1263876
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Behaves like C's format string function
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*/
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export function formatText() {
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let args = arguments,
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string = args[0],
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i = 1;
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return string.replace(/%((%)|s|d)/g, (m) => {
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// m is the matched format, e.g. %s, %d
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let val = null;
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if (m[2]) {
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val = m[2];
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} else {
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val = args[i];
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// A switch statement so that the formatter can be extended. Default is %s
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switch (m) {
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case '%d':
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val = parseFloat(val);
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if (isNaN(val)) {
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val = 0;
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}
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break;
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}
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i++;
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}
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return val;
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});
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}
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/*
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Checks a list of objects for key duplicates and returns a boolean
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*/
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function _doesObjectListHaveDuplicates(l) {
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let mergedList = [];
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l = l.map((obj) => {
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if(!obj) {
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throw new Error('The object you are trying to merge is null instead of an empty object');
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}
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return Object.keys(obj);
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});
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// Taken from: http://stackoverflow.com/a/10865042
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// How to flatten an array of arrays in javascript.
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// If two objects contain the same key, then these two keys
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// will actually be represented in the merged array
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mergedList = mergedList.concat.apply(mergedList, l);
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// Taken from: http://stackoverflow.com/a/7376645/1263876
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// By casting the array to a set, and then checking if the size of the array
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// shrunk in the process of casting, we can check if there were any duplicates
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return (new Set(mergedList)).size !== mergedList.length;
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}
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/**
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* Takes a list of object and merges their keys to one object.
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* Uses mergeOptions for two objects.
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* @param {[type]} l [description]
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* @return {[type]} [description]
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*/
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export function mergeOptions(...l) {
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// If the objects submitted in the list have duplicates,in their key names,
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// abort the merge and tell the function's user to check his objects.
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if(_doesObjectListHaveDuplicates(l)) {
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throw new Error('The objects you submitted for merging have duplicates. Merge aborted.');
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}
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let newObj = {};
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for(let i = 1; i < l.length; i++) {
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newObj = _mergeOptions(newObj, _mergeOptions(l[i - 1], l[i]));
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}
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return newObj;
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}
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/**
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* Takes a list of object and merges their keys to one object.
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* Uses mergeOptions for two objects.
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* @param {[type]} l [description]
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* @return {[type]} [description]
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*/
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export function mergeOptionsWithDuplicates(...l) {
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// If the objects submitted in the list have duplicates,in their key names,
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// abort the merge and tell the function's user to check his objects.
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let newObj = {};
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for(let i = 1; i < l.length; i++) {
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newObj = _mergeOptions(newObj, _mergeOptions(l[i - 1], l[i]));
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}
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return newObj;
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}
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/**
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* In place update of a dictionary
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*/
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export function update(a, ...l) {
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for(let i = 0; i < l.length; i++) {
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for (let attrname in l[i]) {
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a[attrname] = l[i][attrname];
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}
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}
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return a;
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}
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/**
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* Overwrites obj1's values with obj2's and adds obj2's if non existent in obj1
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* @param obj1
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* @param obj2
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* @returns obj3 a new object based on obj1 and obj2
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* Taken from: http://stackoverflow.com/a/171256/1263876
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*/
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function _mergeOptions(obj1, obj2) {
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let obj3 = {};
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for (let attrname in obj1) {
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obj3[attrname] = obj1[attrname];
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}
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for (let attrname in obj2) {
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obj3[attrname] = obj2[attrname];
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}
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return obj3;
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}
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