'use strict'; /** * Takes an object and deletes all keys that are * * tagged as false by the passed in filter function * * @param {object} obj regular javascript object * @return {object} regular javascript object without null values or empty strings */ export function sanitize(obj, filterFn) { if(!filterFn) { // By matching null with a double equal, we can match undefined and null // http://stackoverflow.com/a/15992131 filterFn = (val) => val == null || val === ''; } Object .keys(obj) .map((key) => { if(filterFn(obj[key])) { delete obj[key]; } }); return obj; } /** * Sums up a list of numbers. Like a Epsilon-math-kinda-sum... */ export function sumNumList(l) { let sum = 0; l.forEach((num) => sum += parseFloat(num) || 0); return sum; } /* Taken from http://stackoverflow.com/a/4795914/1263876 Behaves like C's format string function */ export function formatText() { let args = arguments, string = args[0], i = 1; return string.replace(/%((%)|s|d)/g, (m) => { // m is the matched format, e.g. %s, %d let val = null; if (m[2]) { val = m[2]; } else { val = args[i]; // A switch statement so that the formatter can be extended. Default is %s switch (m) { case '%d': val = parseFloat(val); if (isNaN(val)) { val = 0; } break; } i++; } return val; }); } /* Checks a list of objects for key duplicates and returns a boolean */ function _doesObjectListHaveDuplicates(l) { let mergedList = []; l = l.map((obj) => { if(!obj) { throw new Error('The object you are trying to merge is null instead of an empty object'); } return Object.keys(obj); }); // Taken from: http://stackoverflow.com/a/10865042 // How to flatten an array of arrays in javascript. // If two objects contain the same key, then these two keys // will actually be represented in the merged array mergedList = mergedList.concat.apply(mergedList, l); // Taken from: http://stackoverflow.com/a/7376645/1263876 // By casting the array to a set, and then checking if the size of the array // shrunk in the process of casting, we can check if there were any duplicates return (new Set(mergedList)).size !== mergedList.length; } /** * Takes a list of object and merges their keys to one object. * Uses mergeOptions for two objects. * @param {[type]} l [description] * @return {[type]} [description] */ export function mergeOptions(...l) { // If the objects submitted in the list have duplicates,in their key names, // abort the merge and tell the function's user to check his objects. if(_doesObjectListHaveDuplicates(l)) { throw new Error('The objects you submitted for merging have duplicates. Merge aborted.'); } let newObj = {}; for(let i = 1; i < l.length; i++) { newObj = _mergeOptions(newObj, _mergeOptions(l[i - 1], l[i])); } return newObj; } /** * Takes a list of object and merges their keys to one object. * Uses mergeOptions for two objects. * @param {[type]} l [description] * @return {[type]} [description] */ export function mergeOptionsWithDuplicates(...l) { // If the objects submitted in the list have duplicates,in their key names, // abort the merge and tell the function's user to check his objects. let newObj = {}; for(let i = 1; i < l.length; i++) { newObj = _mergeOptions(newObj, _mergeOptions(l[i - 1], l[i])); } return newObj; } /** * In place update of a dictionary */ export function update(a, ...l) { for(let i = 0; i < l.length; i++) { for (let attrname in l[i]) { a[attrname] = l[i][attrname]; } } return a; } /** * Overwrites obj1's values with obj2's and adds obj2's if non existent in obj1 * @param obj1 * @param obj2 * @returns obj3 a new object based on obj1 and obj2 * Taken from: http://stackoverflow.com/a/171256/1263876 */ function _mergeOptions(obj1, obj2) { let obj3 = {}; for (let attrname in obj1) { obj3[attrname] = obj1[attrname]; } for (let attrname in obj2) { obj3[attrname] = obj2[attrname]; } return obj3; }